Discuss the continuity on 0 ≤ x ≤ 1 & differentiability at x = 0 for the function.
f(x) =
where x ≠ 0, x ≠
& f(0) = f (1/r π ) = 0, r = 1, 2, 3,.......
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
continuous in 0 ≤ x ≤ 1 & not differentiable at x = 0
Sol. y = f(x) = xsin 1/x. sin
when x ≠ 0,
, r = 1,2,3
y = 0, x = 0,
where r = 1,2,3,...............
Let t = x sin1/x as x → 0 + , t 
and as x
, t
0
y = t sin1/t
= f(0) also
= f 
f(x) is continous at x = 0 and
⇒ f(x) is continous 
We know that t = xsin1/x is not differentiable at x = 0
therefore y = tsin1/t = xsin1/x. sin
is not differentiable at x = 0
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems